To find the flow rates
((100,000 tonne C_9 H_12)/year)×((1,000 kg)/(1 tonne))×((1 mol)/(.12019 kg))×((1 year)/(365 days))×((1 day)/(24 hours))=94.98kmol⁄h of cumene produced
n ̇_1=n ̇_3+((94.98 kmol C_9 H_12)/h)×((1 mol C_9 H_12)/(〖1 mol C〗_3 H_6 ))
n ̇_3=.1n ̇_1
n ̇_1=.1n ̇_1+94.98 kmol⁄h C_3 H_6
n ̇_1=105.5 kmol⁄h
n ̇_3=10.5 kmol⁄h
For a ration of fresh feed to recycle feed of 1:3
n ̇_2=((94.98 kmol C_9 H_12)/h)×((1 mol C_9 H_12)/(〖1 mol C〗_6 H_6 ))×((〖4 mol C〗_6 H_6 fed)/(〖1 mol C〗_6 H_6 fresh feed))
n ̇_2=379.9 kmol⁄h
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